0=4x^2-17x+18

Solution for 0=4x^2-17x+18 equation:

0=4x^2-17x+18

We move all terms to the left:

0-(4x^2-17x+18)=0

We add all the numbers together, and all the variables

-(4x^2-17x+18)=0

We get rid of parentheses

-4x^2+17x-18=0

a = -4; b = 17; c = -18;
Δ = b2-4ac
Δ = 172-4·(-4)·(-18)
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1}=1$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(17)-1}{2*-4}=\frac{-18}{-8}
=2+1/4
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(17)+1}{2*-4}=\frac{-16}{-8}
=+2
$